Final answer:
To solve the quadratic equation for x, rearrange it into standard form, apply the quadratic formula, find the potential solutions, and select the plausible one after considering the context.
Step-by-step explanation:
To solve the question for x, let's first understand that it appears to be a quadratic equation we are dealing with. The goal is to rearrange the equation to a standard form of ax² + bx + c = 0 and then apply the quadratic formula. An example of a rearranged equation is x² + 1.2 x 10-2x - 6.0 × 10-3 = 0. Using the quadratic formula, which is x = (-b ± √(b² - 4ac)) / (2a), we can solve for the potential values of x.
After calculating, we may find two potential solutions for x, for example, x = -.0024, and x = .00139. However, if we face a situation where one of the solutions doesn't make sense in the context of the problem (such as negative concentration in chemistry that can't exist in real life), we would disregard the non-sensical solution and accept the one that's plausible, applying any necessary rounding.
Lastly, always remember to eliminate terms that are negligible, check that your answer is reasonable and within the expected range given the context.