Final answer:
To calculate the probability that Sean doesn't win either a game of chess or pool, we multiply the probabilities of losing each game, assuming both are independent events with a loss probability of 0.57, yielding a result of around 32.49%.
Step-by-step explanation:
To work out the probability that Sean does not win either a game of chess or a game of pool, we must consider the individual probabilities of losing each game. If we assume that the probability of losing each game is similar to the probabilities given in the example information, we could use a value like 0.57 for losing a game of chess.
For the game of pool, no specific probability is given, but if we were to assume a probability, let's use 0.57 for consistency, representing the probability of losing the game of pool as well.
Since the games are independent events, we can calculate the overall probability of losing both games by multiplying the probabilities of losing each game:
Probability of losing both games = Probability of losing chess × Probability of losing pool = 0.57 × 0.57
This results in an answer of 0.3249 or roughly 32.49% chance that Sean doesn't win either of the two games.