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What is the mass, in grams (g), of 0.042 liters (L) of concentrated sulfuric acid with a density of 1.19 g/mL? What is the volume, in milliliters (mL), of 30.0 grams of concentrated sulfuric acid with a density of 1.19 g/mL?

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Final answer:

The mass of 0.042 liters of concentrated sulfuric acid with a density of 1.19 g/mL is 49.98 grams, and the volume of concentrated sulfuric acid that has a mass of 30.0 grams with the same density is 25.21 milliliters.

Step-by-step explanation:

To calculate the mass of the sulfuric acid, we multiply the volume of the sulfuric acid by its density. For 0.042 liters (which is the same as 42 mL since 1 L = 1000 mL), the calculation is as follows: 42 mL × 1.19 g/mL = 49.98 g. Therefore, the mass of 0.042 liters of concentrated sulfuric acid is 49.98 grams.

To find the volume of sulfuric acid that contains 30.0 grams, we divide the mass by the density. The calculation is: 30.0 g ÷ 1.19 g/mL = 25.21 mL. So, the volume of concentrated sulfuric acid that contains 30.0 grams is 25.21 milliliters.

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