Question

How many moles of NaCl are produced when 1.2 moles of HCl and 3.8 moles of NaOH react according to the equation HCl + NaOH → NaCl + H₂O?

A) 1.2 moles
B) 3.8 moles
C) 5.0 moles
D) 2.6 moles

Answer 1

1.2 moles of NaCl are produced when 1.2 moles of HCl react with NaOH according to the 1:1 mole ratio in the balanced chemical equation; the excess NaOH does not affect the amount of NaCl produced.

Step-by-step explanation:

In the Titration Experiment, the balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) is as follows: HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l). According to the equation, the mole ratio of HCl to NaOH is 1:1. This means that 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of NaCl.

Given that you have 1.2 moles of HCl and 3.8 moles of NaOH, you are limited by the smaller amount, which is 1.2 moles of HCl. Therefore, 1.2 moles of NaOH will react with the 1.2 moles of HCl to form 1.2 moles of NaCl.

To summarize, you can produce a maximum of 1.2 moles of NaCl as this is the amount limited by the HCl present, adhering to the 1:1 mole ratio of the balanced equation. So, the correct answer is A) 1.2 moles.