Final answer:
The magnitude of the force exerted on the scooter is found by calculating the acceleration first and then using Newton's second law of motion (F = ma). The calculated force exerted is 917.5 Newtons.
Step-by-step explanation:
The question involves calculating the force exerted on a scooter over a given time interval during which its velocity changes. The scooter's mass and the change in velocity are provided, as well as the time interval over which this change occurs. To determine the force, we can apply Newton's second law of motion, which states that the force is equal to the mass times the acceleration (F = ma). First, we find the acceleration (a) by using the formula a = (v_f - v_i) / t, where v_f is the final velocity, v_i is the initial velocity, and t is the time. Plugging in the values, we get a = (28 m/s - 6 m/s) / 6 s = 22 m/s / 6 s = 3.67 m/s². Now, using the mass of the scooter (m = 250 kg), we can find the force: F = m a = 250 kg 3.67 m/s², which gives us F = 917.5 N. Therefore, the magnitude of the force exerted on the scooter is 917.5 Newtons.