Final Answer:
The number of moles of ammonia formed when a 8.256 mole sample of dinitrogen tetrahydride completely decomposes is 16.512 moles.
Step-by-step explanation:
Dinitrogen tetrahydride (N₂H₄) decomposes into ammonia (NH₃) and nitrogen gas (N₂) according to the balanced chemical equation:
N₂H₄(l) → 2NH₃(g) + N₂(g)
From the balanced equation, we can see that 1 mole of dinitrogen tetrahydride yields 2 moles of ammonia. To find the moles of ammonia produced from the given 8.256 mole sample of dinitrogen tetrahydride, we use the stoichiometric ratio:
8.256 moles N₂H₄ x 2 moles NH₃/ 1 mole N₂H₄ = 16.512 moles NH₃
Therefore, 16.512 moles of ammonia are formed.
This result is derived from the conservation of moles in a chemical reaction. As 1 mole of dinitrogen tetrahydride produces 2 moles of ammonia, we multiply the given moles of dinitrogen tetrahydride by the ratio of moles of ammonia to moles of dinitrogen tetrahydride. This calculation ensures that we account for the stoichiometry of the reaction, providing an accurate representation of the reactants' conversion to products.