Question

Determine the milligrams of h2o produced when 0.485 grams of o2 reacts with h2 according to the following reactionh₂(g) o₂(g) → h₂o(l):

Answer 1

To determine the mass of water produced, a proportion based on the stoichiometry of the balanced chemical reaction is used, with 32.00 grams of oxygen yielding 36.03 grams of water.

Step-by-step explanation:

The question is asking to determine the mass of water (H₂O) produced when a given mass of oxygen (O₂) reacts with hydrogen (H₂) in a chemical reaction. The balanced chemical equation for this reaction is:

2 H₂(g) + O₂(g) → 2 H₂O(l)

Using the stoichiometry of the reaction, we find that 32.00 grams of O₂ will produce 36.03 grams of H₂O. Since the mass of O₂ that reacted is 0.485 grams, we can set up a proportion to solve for the mass of H₂O produced:

(0.485 g O₂) / (32.00 g O₂) = (x g H₂O) / (36.03 g H₂O)

After solving for x, we find:

x = (0.485 g O₂) × (36.03 g H₂O) / (32.00 g O₂)

Therefore, the mass of H₂O produced is the value of x.