Question

Copper(ii) phthalocyanine (cu(c₃₂h₁₆n₈)) is produced by the cyclotetramerization of phthalonitrile (c₈h₄n₂) according to the following reaction: c₈h₄n₂(l) cucl₂(s) → cu(c₃₂h₁₆n₈)(s) cl₂(g) how many moles of copper(ii) phthalocyanine would be produced by the complete cyclotetramerization of 667 grams of phthalonitrile in the presence of excess copper(ii) chloride?

Answer 1

To determine the number of moles of copper(II) phthalocyanine produced, we can use stoichiometry. The balanced equation shows that for every mole of phthalonitrile reacted, one mole of copper(II) phthalocyanine is produced. Converting the mass of phthalonitrile to moles gives us the number of moles of copper(II) phthalocyanine produced.

Step-by-step explanation:

To determine the number of moles of copper(II) phthalocyanine produced, we need to use stoichiometry. The balanced equation for the reaction is:

C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g)

From the equation, we can see that the stoichiometric ratio between phthalonitrile (C₈H₄N₂) and copper(II) phthalocyanine (Cu(C₃₂H₁₆N₈)) is 1:1. This means that for every mole of phthalonitrile reacted, one mole of copper(II) phthalocyanine is produced.

To find the number of moles of copper(II) phthalocyanine produced, we need to convert the mass of phthalonitrile to moles. The molar mass of phthalonitrile is 128 g/mol, so:

Number of moles of phthalonitrile = Mass of phthalonitrile / Molar mass of phthalonitrile

Number of moles of phthalonitrile = 667 g / 128 g/mol = 5.21 mol

Since the stoichiometric ratio is 1:1, the number of moles of copper(II) phthalocyanine produced is also 5.21 mol.