Final answer:
The force of static friction acting on the luggage with a mass of 68 kg and a coefficient of static friction of 0.7 is 466 N.
Step-by-step explanation:
When you pull on a stationary mass with a force 255 N and it does not move, it means that the force of static friction is equal to or greater than the applied force.
The force of static friction can be calculated using the formula: fs = μ_s × N, where μ_s is the coefficient of static friction and N is the normal force (the force exerted by the surface perpendicularly, which is usually the weight of the object).
For an object with a mass of 68 kg, the weight, and hence the normal force, N, would be mg = 68 kg × 9.80 m/s² = 666.4 N. With a coefficient of static friction μ_s of 0.7, the maximum static friction force would be fs = 0.7 × 666.4 N = 466.48 N.
Therefore, the force of static friction acting on the luggage is 466 N, which corresponds to option b.