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Consider the 73 n weight held by two cables shown below. the left-hand cable is horizontal. 73 n 52 ◦ a) what is the tension in the cable slanted at an angle of 52◦ ? answer in units of n.

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The tension in the cable slanted at an angle of 52° is calculated by dividing the weight of the object by the cosine of the angle. This determines the tension needed to balance the object's weight vertically.

To find the tension in the cable slanted at an angle of 52°, we can consider the vertical component of the tension since it must balance the weight of the 73 N object. As the left-hand cable is horizontal, it only provides a horizontal force and therefore does not contribute to supporting the vertical weight. Using trigonometry, the tension T in the slanted cable is equal to the weight divided by the cosine of the angle:

T = weight / cos(angle) = 73 N / cos(52°)

Calculating this gives us the tension in the slanted cable, which is the final answer.

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