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Write the quadtratic equation that as roots (-1-sqrt2)/3 and (-1 sqrt2)/3 if its coefficient with x^2 is equal to 9

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Final answer:

The quadratic equation with roots (-1-√2)/3 and (-1+√2)/3 and a leading coefficient of 9 can be written by multiplying out 9(x - (-1-√2)/3)(x - (-1+√2)/3).

Step-by-step explanation:

The student is asked to write a quadratic equation whose roots are (-1-√2)/3 and (-1+√2)/3, and whose leading coefficient, the coefficient with x^2, is 9. To find such an equation, we use the fact that if α and β are the roots of the quadratic equation ax^2 + bx + c = 0, then the equation can be expressed as a(x - α)(x - β) = 0. Plugging in the roots provided and the leading coefficient, we get the equation 9(x - (-1-√2)/3)(x - (-1+√2)/3) = 0.

By simplifying this equation, we will arrive at the desired quadratic equation.

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