Final answer:
To determine the volume of hydrogen gas produced from 25.3 g of zinc reacting with hydrochloric acid, one must calculate the moles of zinc, then use the stoichiometry of the reaction and ideal gas law to find the volume at standard temperature and pressure.
Step-by-step explanation:
Calculating the Volume of Hydrogen Gas
To calculate the volume of hydrogen gas produced when 25.3 g of zinc metal reacts with hydrochloric acid, we must first determine the number of moles of zinc. We use the molar mass of zinc, which is 65.4 g/mol, to find the moles of zinc in 25.3 g.
Next, we apply the chemical reaction between zinc and hydrochloric acid (HCl), which is:
Zn(s) + 2 HCl(aq) → ZnCl₂ (aq) + H₂(g)
This reaction tells us that one mole of zinc reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas. Assuming we have excess HCl, the amount of hydrogen produced will be directly related to the amount of zinc.
Upon calculating the moles of zinc, we then use the ideal gas law, PV = nRT, to find the volume of hydrogen gas produced at a given temperature and pressure. The ideal gas constant (R) is 0.0821 L · atm/(mol · K) and we assume standard temperature and pressure for the calculation.