Final answer:
To find the reaction enthalpy under standard conditions for the given reaction, you need to apply the formula ∆H° = Σ∆H°f (products) - Σ∆H°f (reactants), using the standard enthalpies of formation and the stoichiometric coefficients from the balanced chemical equation.
Step-by-step explanation:
To calculate the reaction enthalpy of the chemical reaction 2CH3OH(l) + 3O2(g) → 2CO2(g) + 4H2O(l) under standard conditions, we would typically use standard enthalpies of formation for each compound. The standard enthalpy change (∆H°) for a reaction can be found using the formula:
- ∆H° = Σ∆H°f (products) - Σ∆H°f (reactants)
Each substance’s standard molar enthalpy of formation must be multiplied by its stoichiometric coefficient in the balanced equation. Once the correct values are obtained and plugged into the formula above, the result will provide the reaction enthalpy in kilojoules, rounded to the nearest kJ as per the requirement.