Final answer:
The density of metal B13-Z is calculated by dividing its mass in grams (851 g) by its volume in cm3 (5.9 cm3), resulting in approximately 144.24 g/cm3.
Step-by-step explanation:
To calculate the density of metal B13-Z, we must find the mass of the metal and its volume. You have provided the mass of the metal as 0.851 kg, which equals 851 grams (since 1 kg = 1000 grams). The volume of the metal is the difference between the final volume of water and the initial volume of water. So, the volume of metal B13-Z is 19.2 mL (final volume) - 13.3 mL (initial volume) = 5.9 mL, which is the same as 5.9 cm3 (since 1 mL = 1 cm3).
To find the density, we use the formula density = mass / volume. Therefore, the density of metal B13-Z is 851 g / 5.9 cm3 = approximately 144.24 g/cm3.
Thinking about the result, we know that metals generally have a higher density than water — for example, 1 cm3 of zinc has a mass of about 7 grams. Given that the density of B13-Z is significantly greater than that of water (1 g/cm3), which is around the same as zinc's density, it supports the expectation for metallic densities.