49.6k views
0 votes
Calculate the mass percent by volume of 256.6 g of glucose (c6h12 mm = 180.2 g/mil) in 325ml of solution

User Whitenexx
by
7.6k points

1 Answer

4 votes

Final answer:

The mass percent by volume of a glucose solution with 256.6 g of glucose in 325 mL of solution is calculated using the mass/volume percent formula and is found to be 78.95%.

Step-by-step explanation:

To calculate the mass percent by volume of glucose in solution, we use the following formula:

Mass/Volume % (m/v) = (mass of solute in grams / volume of solution in milliliters) x 100%

Given the mass of glucose (C6H12O6) is 256.6 g, and the volume of the solution is 325 mL:

Mass/Volume % = (256.6 g / 325 mL) x 100%

This equation will yield the mass percent by volume of the glucose solution.

Now let's do the calculation:

Mass/Volume % = (256.6 / 325) x 100% = 78.95%

So, the mass percent by volume of glucose in the solution is 78.95%.

User Dustin Getz
by
7.8k points