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Calculate δh when 9.21×10−4mol of agcl dissolves in water.

User Boulder
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Final answer:

The solubility of AgCl in pure water at 25°C can be calculated using the solubility product constant (Ksp). The Ksp for AgCl is given as 1.77 × 10-10. Using the equation Ksp = [Ag+][Cl-], we can assume that x represents the concentration of Ag+ and Cl- ions in solution. The solubility of AgCl in pure water at 25°C is 1.33 × 10^-5 M.

Step-by-step explanation:

The solubility of AgCl in pure water at 25°C can be calculated using the solubility product constant (Ksp). The Ksp for AgCl is given as 1.77 × 10-10. Using the equation Ksp = [Ag+][Cl-], we can assume that x represents the concentration of Ag+ and Cl- ions in solution. By solving for x, we find that the solubility of AgCl in pure water at 25°C is 1.33 × 10-5 M.

The solubility of AgCl in pure water at 25°C can be calculated using the solubility product constant (Ksp). The Ksp for AgCl is given as 1.77 × 10-10. Using the equation Ksp = [Ag+][Cl-], we can assume that x represents the concentration of Ag+ and Cl- ions in solution. The solubility of AgCl in pure water at 25°C is 1.33 × 10^-5 M.

User Woblob
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