Final answer:
The statement which true is `If Colleen selected one egg, cracked it open and found out it was raw, the probability of selecting the hard-boiled egg on her second pick is 1/5.`
The answer is option ⇒1
Step-by-step explanation:
To understand why this statement is true, let's consider the possible scenarios. Colleen has 6 eggs, one of which is hard-boiled and the rest are raw. If she randomly selects an egg and cracks it open, there are two possibilities:
1. If she selected a raw egg on her first try, there would be 5 eggs left, including the hard-boiled one. Therefore, the probability of selecting the hard-boiled egg on her second pick would be 1 out of the remaining 5 eggs, which is 1/5.
2. If she selected the hard-boiled egg on her first try, there would also be 5 eggs left, but all of them would be raw. Therefore, the probability of selecting the hard-boiled egg on her second pick would still be 0 out of the remaining 5 eggs, which is 0/5 or 0.
Since there is a 1/5 chance of selecting a raw egg on the first try, and if that happens, there is a 1/5 chance of selecting the hard-boiled egg on the second try, the correct statement is that the probability of selecting the hard-boiled egg on her second pick is 1/5.
The answer is option ⇒1
Your question is incomplete, but most probably the full question was:Colleen has 6 eggs, one of which is hard-boiled while the rest are raw. Colleen can't remember which of the eggs are raw.
Which of the following statements is true?
- If Colleen selected one egg, cracked it open and found out it was raw, the probability of selecting the hard-boiled egg on her second pick is 1/5.
- The probability of Colleen selecting the hard-boiled egg on her first try is 1/5.
- The probability of Colleen selecting a raw egg on her first try is 1/6.
- If Colleen selected one egg, cracked it open and found out it was raw, the probability of selecting the hard-boiled egg on her second pick is 1/6.