Question

Calculate the molarity of the following solutions.27.5 g of naoh in 300. ml of a naoh solution

Answer 1

The molarity of a NaOH solution with 27.5 g of NaOH dissolved in 300 mL of solution is 2.29 M. This is calculated by converting the mass of NaOH to moles, converting the volume to liters, and then using the molarity formula.

Step-by-step explanation:

To calculate the molarity of a NaOH solution when 27.5 g of NaOH is dissolved in 300 mL of solution, you need to use the formula:

Molarity (M) = moles of solute / liters of solution

First, convert the mass of NaOH to moles:

Moles = mass (g) / molar mass (g/mol)

The molar mass of NaOH is approximately 40 g/mol.

Moles NaOH = 27.5 g / 40 g/mol = 0.6875 mol

Next, convert the volume of the solution to liters:

300 mL = 0.3 L

Now calculate the molarity:

Molarity = 0.6875 mol / 0.3 L = 2.29 M

So, the molarity of the NaOH solution is 2.29 M.