41.4k views
4 votes
A suburban specialty restaurant has developed a single drive-thru window. customers order, pay, and pick up their food at the same window. arrivals follow a poisson distribution while service times follow an exponential distribution. if the average number of arrivals is 6 per hour and the service rate is 2 every 15 minutes, how much time will elapse (in hours) from the time a customer enters the line until he/she leaves the restaurant?

1 Answer

5 votes

Final answer:

The average time a customer will spend from entering the line to leaving the restaurant is 0.5 hours or 30 minutes, considering the arrival rate (λ) is 6 per hour and the service rate (μ) is 8 per hour.

Step-by-step explanation:

The question involves queueing theory, where the arrivals follow a Poisson distribution and service times follow an exponential distribution. Given the average number of arrivals is 6 per hour, we can find the average time between arrivals. Also, with a service rate of 2 every 15 minutes, or 8 per hour, we can determine the average service time as well.

a. The average time between two successive arrivals (arrival rate λ) can be calculated as:
1 hour / 6 arrivals = 0.1667 hours (or 10 minutes).

b. The average service rate (μ) is:
2 services / 15 minutes = 8 services / 1 hour.
Hence, the average service time is:
1 hour / 8 services = 0.125 hours (or 7.5 minutes).

The total average time a customer spends in the system (system time) is the sum of the average service time and the time waiting in line. This is often modeled as 1 / (μ - λ) for M/M/1 queue:

System Time = 1 / (μ - λ) = 1 / (8 - 6) = 1 / 2
= 0.5 hours (or 30 minutes).

User Furkan Mustafa
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories