Final answer:
To choose 10 bowlers from a group of 35 (15 left-handed and 20 right-handed bowlers), there are 3,193,056 ways to do so.
Step-by-step explanation:
To find the number of ways to choose 10 bowlers from a group of 15 left-handed bowlers and 20 right-handed bowlers, we can use the combination formula. The combination formula is nCr = n! / ((n-r)! * r!), where n is the total number of bowlers and r is the number of bowlers we want to choose.
Using this formula, we can calculate 35C10 to find the number of ways to choose 10 bowlers from a group of 35 bowlers. Evaluating this expression, we have:
35C10 = 35! / ((35-10)! * 10!)
= 35! / (25! * 10!)
= (35 * 34 * 33 * 32 * 31 * 30 * 29 * 28 * 27 * 26) / (10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)
= 3,193,056 ways
Your question is incomplete but most probably your full question was
A team of 10 bowlers will be selected from a group consisting of 15 left-handed bowlers and 20 right-handed bowlers. How many ways can the 10 bowlers be chosen?