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A team of 10 bowlers will be selected from a group consisting of 15 left-handed bowlers and 20 right-handed bowlers.

User COil
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1 Answer

1 vote

Final answer:

To choose 10 bowlers from a group of 35 (15 left-handed and 20 right-handed bowlers), there are 3,193,056 ways to do so.

Step-by-step explanation:

To find the number of ways to choose 10 bowlers from a group of 15 left-handed bowlers and 20 right-handed bowlers, we can use the combination formula. The combination formula is nCr = n! / ((n-r)! * r!), where n is the total number of bowlers and r is the number of bowlers we want to choose.

Using this formula, we can calculate 35C10 to find the number of ways to choose 10 bowlers from a group of 35 bowlers. Evaluating this expression, we have:

35C10 = 35! / ((35-10)! * 10!)

= 35! / (25! * 10!)

= (35 * 34 * 33 * 32 * 31 * 30 * 29 * 28 * 27 * 26) / (10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)

= 3,193,056 ways

Your question is incomplete but most probably your full question was

A team of 10 bowlers will be selected from a group consisting of 15 left-handed bowlers and 20 right-handed bowlers. How many ways can the 10 bowlers be chosen?

User Lordzuko
by
8.3k points
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