Final answer:
The rabbit's speed when it lands will be the same as its initial speed of 1.48 m/s due to the conservation of energy in projectile motion, which is 1.48 m/s.
Step-by-step explanation:
The question relates to basic physics principles, specifically the conservation of energy in the context of projectile motion. When a rabbit jumps straight up with an initial velocity, it will have the same speed when it lands as when it took off (neglecting air resistance and assuming it lands back at the same height). Therefore, if the rabbit jumps up with an initial velocity of 1.48 m/s, its speed when it lands will also be 1.48 m/s.