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A sample of water is heated from 10.0c to 15.0c by the addition of 30. joules of heat. what is the mass of the water?

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Final answer:

To determine the mass of the water that was heated, we use the formula q = mcΔT. With the given heat energy (30 J), specific heat capacity of water (4.184 J/g°C), and temperature change (5.0°C), the mass of the water is found to be approximately 1.43 grams.

Step-by-step explanation:

To find the mass of the water heated from 10.0°C to 15.0°C by the addition of 30 J of heat, we can use the formula q = mcΔT, where q is the heat energy (30 J), m is the mass, c is the specific heat capacity of water (4.184 J/g°C), and ΔT is the change in temperature (ΔT = 15.0°C - 10.0°C = 5.0°C). By rearranging the formula to solve for m, we get m = q / (cΔT).

Substituting the values gives: To determine the mass of the water that was heated, we use the formula q = mcΔT. With the given heat energy (30 J), specific heat capacity of water (4.184 J/g°C), and temperature change (5.0°C), the mass of the water is found to be approximately 1.43 grams.

m = 30 J / (4.184 J/g°C × 5.0°C) = 30 J / (20.92 J/g) = 1.43 g (rounded to two decimal places)

Therefore, the mass of the water is approximately 1.43 grams.

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