Final answer:
To determine the grams of CO2 produced, we need to identify the limiting reactant and use stoichiometry. In this case, CO is the limiting reactant. By calculating the moles of CO and using the stoichiometric coefficients, we find that 0.339 mol of CO2 can be produced. Finally, we convert the moles to grams and find that 14.92 g of CO2 can be produced.
Step-by-step explanation:
To determine the amount of CO₂ that could be produced, we first need to identify the limiting reactant in the reaction. This is done by comparing the given amounts of CO and O₂ to their stoichiometric coefficients in the balanced equation.
Since the ratio of CO to O₂ is 1:1 in the balanced equation, we can see that both reactants have an equal number of moles. Therefore, the limiting reactant is the one with the smaller molar mass, which is CO.
Next, we calculate the number of moles of CO by dividing the given mass by its molar mass. The molar mass of CO is approximately 28.01 g/mol:
Moles of CO = 9.50 g CO / 28.01 g/mol CO = 0.339 mol CO
Since 1 mol of CO reacts to produce 1 mol of CO₂, we can calculate the moles of CO₂ produced:
Moles of CO₂ produced = 0.339 mol CO * (2 mol CO₂ / 2 mol CO) = 0.339 mol CO₂
Finally, we can convert the moles of CO₂ to grams:
Mass of CO₂ produced = 0.339 mol CO₂ * 44.01 g/mol CO₂ = 14.92 g CO₂