Question

A rigid ball that contained 25.0 liters of air at 22° c and 6.25 atm pressure was placed in an oven at a temperature of 100 ° c what was the new pressure

Answer 1

The new pressure inside the rigid ball after being placed in the oven is 7.91 atm.

Step-by-step explanation:

To find the new pressure of the air inside the rigid ball, we can use the ideal gas law equation:

P₁V₁/T₁ = P₂V₂/T₂

Where P₁ and T₁ are the initial pressure and temperature, V₁ is the initial volume, P₂ is the final pressure, V₂ is the final volume, and T₂ is the final temperature.

Plugging in the given values:

P₁ = 6.25 atm

V₁ = 25.0 L

T₁ = 22°C = 295 K

T₂ = 100°C = 373 K

Solving for P₂:

P₂ = (P₁ * V₁ * T₂) / (V₂ * T₁)

P₂ = (6.25 atm * 25.0 L * 373 K) / (25.0 L * 295 K)

P₂ = 7.91 atm

Therefore, the new pressure inside the rigid ball after being placed in the oven is 7.91 atm.