Question

A population of oysters is being studied at the prlq gene to determine if the population is evolving with respect to that gene. the following genotypes have been observed out of a sample of 501 oysters: qq = 61, qq = 202, and qq = 238. the chi-squared significance cut-off value is 3.841. based on these data, and what is expected under hardy-weinberg equilibrium, what can we say about this population?

Answer 1

To determine if a population is evolving, we can compare observed and expected genotype frequencies using the Hardy-Weinberg equation. Applying the chi-squared test to the given data will help determine if the population is in equilibrium or evolving.

Step-by-step explanation:

To determine if a population is evolving with respect to a gene, we can compare the observed genotype frequencies with the expected frequencies under Hardy-Weinberg equilibrium. In this case, the observed genotypes were qq = 61, qq = 202, and qq = 238.

To calculate the expected frequencies, we can use the Hardy-Weinberg equation: p² + 2pq + q² = 1. From the given data, we know that the sample size is 501 oysters, so the total number of genotypes should sum up to 501.

By dividing the observed genotypes by 501, we can convert them into frequencies.

From the expected frequencies, we can calculate the expected number of genotypes by multiplying the expected frequencies by 501.

We can then use the chi-squared test to compare the observed and expected genotypes.

If the chi-squared value is greater than the significance cut-off value (3.841), it indicates that the population is not in Hardy-Weinberg equilibrium and is evolving.