Question

A metal rod with a length of 21.0 cm lies in the xy -plane and makes an angle of 37.5 ∘ with the positive x -axis and an angle of 52.5 ∘ with the positive y -axis. the rod is moving in the x -direction with a speed of 6.80 m/s . the rod is in a uniform magnetic field b⃗ =(0.160t)i^−(0.300t)j^−(0.0800t)k

Answer 1

To find the magnetic force on an electron in the rod, use the equation F = qvb. To find the electric field in the rod, use the equation E = vB. To find the potential difference between the ends of the rod, use the equation V = Φ/L.

Step-by-step explanation:

To find the magnetic force on an electron in the rod, we can use the equation F = qvb, where F is the force, q is the charge of the electron, v is the velocity of the rod, and b is the magnetic field strength. In this case, the charge of an electron is -1.6 x 10^-19 C, the velocity of the rod is 6.80 m/s, and the magnetic field is given as b⃗ =(0.160t)i^−(0.300t)j^−(0.0800t)k. Plugging in these values, we can calculate the magnetic force. To find the electric field in the rod, we can use the equation E = vB, where E is the electric field, v is the velocity of the rod, and B is the magnetic field strength. In this case, the velocity of the rod is 6.80 m/s and the magnetic field is given as b⃗ =(0.160t)i^−(0.300t)j^−(0.0800t)k. Plugging in these values, we can calculate the electric field. To find the potential difference between the ends of the rod, we can use the equation V = Φ/L, where V is the potential difference, Φ is the magnetic flux, and L is the length of the rod. In this case, the length of the rod is 21.0 cm. Since the rod lies in the xy-plane, the magnetic flux through the rod is 0. Using these values, we can calculate the potential difference.