The equation of a line passing through point (-3,4), with a slope of -2 is y = -2x - 2.
The equation of a line in slope-intercept form is expressed as:
y = mx + b
Where m is the slope and b is the y-intercept
Given the parameter:
Slope m = -2
Points:(-3,4)
x₁ = -3 and y₁ = 4
Plug the given slope and point into the formula and solve for the y-intercept b:
y = mx + b
4 = -2(-3) + b
4 = 6 + b
b = 4 - 6
b = -2
Now, plug the slope m = -2 and the y-intercept b = -2 into the formula:
y = mx + b
y = -2x + (-2)
y = -2x - 2
Therefore, the equation of the line is y = -2x - 2.
This question is incomplete, the complete question is:
What is the equation of a line with point (-3,4) and has a slope of -2?