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He electric field within the circle has a magnitude of 300 v/m and is increasing at a rate of 20.8 v/(m · s). in addition, suppose that the radius of the circular area of the electric field increases at a rate of 1.00 cm/s. what would the magnitude of the magnetic field be at point p at this moment (in t)?

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Final answer:

The magnitude of the magnetic field at point P can be calculated using the rate of change of the electric field and the speed of light.

Step-by-step explanation:

To find the magnitude of the magnetic field at point P, we can use Faraday's law of electromagnetic induction, which relates the rate of change of magnetic flux through a closed loop to the electromotive force (EMF) induced in the loop. The formula is given by:

E=− dΦ/dt

where:

E is the induced EMF,

Φ is the magnetic flux.

The magnetic flux (Φ) through the circular loop is given by:

Φ=B⋅A

where:

B is the magnetic field,

A is the area of the circular loop.

The area A of a circle is given by A=πr2, where r is the radius of the circle.

Given that the radius of the circular area (r) is increasing at a rate of 1.00cm/s, we can express this as dr/dt =0.01m/s.

Now, differentiate both sides of the equation Φ=B⋅A with respect to time:

dΦ/dt =B⋅ dA/dt

Substitute the expression for A and the given rate of change of r:

dΦ/dt =B⋅(2πr⋅ dr/dt )

Now, plug this into Faraday's law:

E=−B⋅(2πr⋅ dr/dt)

The induced EMF (E) is also related to the electric field (E) by:

E=B⋅v

where:

v is the velocity of the conducting loop.

In this case, v is the rate at which the radius is increasing, so v= dr/dt

Equating the two expressions for E, we get:

B⋅v=−B⋅(2πr⋅ dr/dt )

Now, solve for the magnetic field (B):

B=−2πr⋅ dr/dt

Now, plug in the given values:

B=−2π⋅(1.00m)⋅(0.01m/s)

Calculate the magnitude of B to find the answer. Note that the negative sign indicates the direction of the induced magnetic field according to Lenz's law.

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