17.7k views
2 votes
Given that n is an integer and that n>1 prove algebraicly n^2-(n-2)^2-2

1 Answer

3 votes

Final answer:

To prove the expression n^2-(n-2)^2-2 algebraically, expand (n-2)^2, subtract it from n^2, and simplify the expression.

Step-by-step explanation:

To prove the expression n^2 - (n-2)^2 - 2, we can simplify it step by step.

1. Start by expanding the square (n-2)^2. This can be done by multiplying (n-2) with itself, giving us n^2 - 4n + 4.

2. Now subtract (n-2)^2 from n^2. This means subtracting n^2 - 4n + 4 from n^2, which results in 4n - 4.

3. Finally, subtract 2 from the expression 4n - 4, giving us the simplified form 4n - 6.

Therefore, the expression n^2 - (n-2)^2 - 2 simplifies to 4n - 6.

In this simplification process, we expanded the square and combined like terms to obtain the final result. By following these steps, we were able to simplify the given expression and arrive at the simplified form 4n - 6.

User Luca Martinetti
by
8.6k points

Related questions

asked Jun 19, 2024 92.0k views
Skim asked Jun 19, 2024
by Skim
7.3k points
1 answer
0 votes
92.0k views
1 answer
4 votes
199k views
asked Jun 14, 2018 66.9k views
Mohit Manhas asked Jun 14, 2018
by Mohit Manhas
8.7k points
1 answer
2 votes
66.9k views