Final answer:
To prove that ps = pk given pq = pr, m∠qpr = m∠spk, and m∠q = m∠prk, we use a proof by contradiction and the congruence of triangles.
Step-by-step explanation:
Proof:
Given: pq = pr, m∠qpr = m∠spk, and m∠q = m∠prk.
To prove: ps = pk
Proof by contradiction:
Assume that ps ≠ pk.
Since pq = pr, and m∠q = m∠prk, we can conclude that triangle pqk is congruent to triangle prk by the SAS (Side-Angle-Side) congruence theorem.
Therefore, ps must be equal to pk, contradicting our initial assumption.
Hence, ps = pk.