Final answer:
To produce 10 grams of calcium carbonate, 11.1 grams of calcium chloride are needed, based on a molar mass calculation and the mole ratio from the balanced chemical equation provided.
Step-by-step explanation:
In order to determine the quantity of calcium chloride needed to produce 10 g of calcium carbonate, one must first review the balanced chemical equation provided: CaCl2 + H2CO3 → CaCO3 + 2HCl. This reaction shows that one mole of calcium chloride reacts to produce one mole of calcium carbonate. To calculate the mass needed, you would:
- Calculate the molar mass of calcium carbonate, CaCO3, which is approximately 100 g/mol.
- Determine the moles of calcium carbonate desired (10 g / 100 g/mol = 0.1 mol).
- Since the mole ratio of calcium chloride to calcium carbonate is 1:1, you would also need 0.1 mol of calcium chloride.
- Calculate the molar mass of calcium chloride, CaCl2, which is approximately 111 g/mol.
- Multiply the moles of calcium chloride needed by its molar mass to find the mass required (0.1 mol * 111 g/mol = 11.1 g).
Therefore, you would need 11.1 grams of calcium chloride to produce 10 grams of calcium carbonate.