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For the decomposition of a to b and c , a(s)⇌b(aq) c(aq) how will the reaction respond to each of the following changes at equilibrium? drag the appropriate items to their respective bins.

User Rsfinn
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Final answer:

The system at equilibrium will adjust in response to changes to minimize the disruption in accordance with Le Châtelier's Principle. For the decomposition reaction A(s) ⇌ B(aq) + C(aq), altering concentrations or temperature can shift the equilibrium left or right, while pressure changes do not significantly affect non-gaseous systems.

Step-by-step explanation:

The question relates to how a reaction at equilibrium responds to various changes. According to Le Châtelier's Principle, a system at equilibrium will adjust to minimize the effect of any changes applied to the system. Here are specific responses to changes for the decomposition reaction A(s) ⇌ B(aq) + C(aq):

  • Increasing the concentration of A will drive the reaction to the right, producing more B and C.
  • Decreasing the concentration of A will drive the reaction to the left, reducing the amounts of B and C formed.
  • Increasing the concentration of B or C will drive the reaction to the left, converting them back into A.
  • Decreasing the concentration of B or C will drive the reaction to the right, forming more of them from A.
  • Increasing the pressure (by decreasing the volume) will not affect this equilibrium significantly since there are no gases involved.
  • Decreasing the pressure (by increasing the volume) will also not have a significant effect for the same reason.
  • Increasing the temperature will depend on whether the reaction is exothermic or endothermic. For exothermic reactions, it drives the reaction to the left, and for endothermic reactions, to the right.
  • Decreasing the temperature has the opposite effect, it will drive exothermic reactions to the right and endothermic reactions to the left.

For gas-phase equilibrium systems, such as the decomposition of CaCO3(s), an increase in volume (decrease in pressure) will shift the equilibrium towards the side with more moles of gas. Conversely, a decrease in volume (increase in pressure) will shift the equilibrium towards the side with fewer moles of gas. This is based on stoichiometry and can be used along with the reaction quotient to predict the direction of the shift.

User JellyFishBoy
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