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Find the radius and center of the circle given by the equation below. ( x – 6) 2 ( y 4) 2 = 7 r = √7 and center at (-4, 6) r = 7 and center at (6, -4) r = 7 and center at (-6, 4) r = √7 and (6, -4)

User Manihtraa
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Final answer:

The correct center of the circle is (6, -4) and the radius is √7, based on the assumed standard form of the circle equation given by the student.

Step-by-step explanation:

The equation for a circle in standard form is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center of the circle, and r is the radius. From the student's question, their equation seems to have a typo but resembles the standard equation of a circle. Assuming the correct form of the equation is (x - 6)^2 + (y + 4)^2 = 7, this would mean the circle has a center at (6, -4) and a radius of √7. This is because in the standard form, the sign of the values inside the parentheses is inverted to find the center, and the value on the right side of the equation is the square of the radius.

User Bug
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