Question

Find the mass percent of cuso4 in a solution whose density is 1.30 g/ml and whose molarity is 1.36 m. a) 83.3% b) 1.77% c) 16.7% d) 2.66% e) none of these

Answer 1

The mass percent of CuSO4 in a 1.36 M solution with a density of 1.30 g/mL is calculated to be approximately 16.7%, which is option (c).

Step-by-step explanation:

To find the mass percent of CuSO4 in the given solution, we first need to determine the mass of CuSO4 in one liter of the solution and then calculate its mass percent.

The molarity (M) indicates moles of solute per liter of solution. For a 1.36 M CuSO4 solution, this means there are 1.36 moles of CuSO4 per liter of solution. The molar mass of CuSO4 is approximately 159.61 g/mol. So, the mass of CuSO4 per liter of solution is:

1.36 moles × 159.61 g/mol = 217.06 g

Given that the solution's density is 1.30 g/mL, the mass of 1 liter (or 1000 mL) of solution is:

1.30 g/mL × 1000 mL = 1300 g

The mass percent of CuSO4 in the solution is:

(Mass of CuSO4 / Mass of the solution) × 100% = (217.06 g / 1300 g) × 100% ≈ 16.7%

Therefore, the correct answer is 16.7%, which corresponds to option (c).