Question

A florist makes a string of flowers along a pole and ties it at a point 20 feet high on the wall and to the floor 8 feet away from the wall. he then changes his mind and moves the flowers down the wall 10 feet. the picture of two right-angle triangles. the lengths of the opposite and adjacent sides of the first triangle are 20 ft and 8 ft. in the second triangle, the opposite side is extended above the hypotenuse and the length is 10 ft. approximately how far away from the wall would he now have to tie the flowers on the floor?

Answer 1

The flowers would have to be tied 4 feet away from the wall on the floor after moving them down 10 feet.

Step-by-step explanation:

The question is asking how far away from the wall the flowers would have to be tied on the floor after the florist moves them down the wall by 10 feet. To solve this problem, we can use the concept of similar triangles. The original triangle has sides measuring 20 feet, 8 feet, and a hypotenuse. The second triangle has sides measuring 10 feet, 8 feet, and a hypotenuse (which extends above the original hypotenuse). Since the triangles are similar, we can set up a proportion:

(20 ft / 8 ft) = (10 ft / x)

Cross-multiplying, we get:

20x = 80

Dividing both sides by 20, we find that x = 4. So, the flowers would have to be tied 4 feet away from the wall on the floor after moving them down 10 feet.