Final answer:
In a cross between two Ff individuals, the genotypic ratio of the offspring is 1:2:1 (FF:Ff:ff) and the phenotypic ratio, assuming F is dominant, is 3:1 dominant to recessive.
Step-by-step explanation:
When you cross two individuals with the genotype Ff, you are performing a monohybrid cross of two heterozygous individuals. To determine the genotypic and phenotypic ratios of the offspring, a Punnett square can be used. In a monohybrid cross of this kind, there are four possible outcomes for the offspring's genotypes: FF, Ff, fF, and ff. Since Ff and fF are the same due to the law of independent assortment, the genotypes can be represented as 1 FF: 2 Ff: 1 ff. This gives a 1:2:1 genotypic ratio.
If we assume that 'F' is a dominant trait, then both FF and Ff genotypes will result in the dominant phenotype. The ff genotype will display the recessive phenotype. Therefore, the phenotypic ratio will be 3 dominant: 1 recessive. Specifically, since F is dominant to f, the offspring would display a 3:1 phenotypic ratio of the dominant trait (F) to the recessive trait (f).