Question

Transformations on graph problemill send a picture of the question

Answer 1

The coordinates of the image B' is;

`(-4,6)`

Step-by-step explanation:

Given the figure in the attached image.

The coordinate of the Preimage B is;

`B(6,4)`

Then rotating it 90 degrees in the counter-clockwise direction;

`(x,y)\rightarrow(-y,x)`

Applying the transformation to the given coordinate, we have;

`B(6,4)\rightarrow B^(\prime)(-4,6)`

Therefore, the coordinates of the image B' is;

`(-4,6)`