Question

In dogs a dominant gene produces wire haired texture recessive allele produces smooth hair a homozygous wire haired male he’s made it to a female a smooth hair show me the punnets square what genotypes and phenotypes are expecting the f1 generation and what ratios

Answer 1

The F1 generation of the cross between a homozygous wire-haired male and a smooth-haired female in dogs will have a genotype of Ww and a phenotype of wire-haired. The ratio of the genotypes and phenotypes in the F1 generation will be 1:0.

Step-by-step explanation:

To determine the genotypes and phenotypes of the F1 generation, we need to understand the inheritance pattern of wire-haired and smooth-haired texture in dogs. In this case, wire-haired texture is determined by a dominant gene (W) and smooth hair is determined by a recessive allele (w). The homozygous wire-haired male is WW, and he is mated with a smooth-haired female (ww). Using a Punnett square, we can determine the genotypes and phenotypes of the F1 generation.

The Punnett square for this cross would look like this:

Ww
WWWWw

Since the wire-haired texture is dominant, all of the F1 offspring will have wire-haired texture. Therefore, the genotypes of the F1 generation will all be Ww and the phenotypes will all be wire-haired. The ratio of the genotypes and phenotypes in the F1 generation will be 1:0 (because all offspring have the same genotype and phenotype)