Question

A piece of iron has a density of 7800 kg/m³ and a volume of 0.012 m³. Find the mass and weight of the iron. The iron is submerged in water. What is the value of the buoyant force on the iron? (Water density is 1000 kg/m³.)

A) Mass: 93.6 kg, Weight: 920 N, Buoyant Force: 117.6 N

B) Mass: 156 kg, Weight: 1528 N, Buoyant Force: 120 N

C) Mass: 156 kg, Weight: 1560 N, Buoyant Force: 140 N

D) Mass: 93.6 kg, Weight: 9200 N, Buoyant Force: 150 N

Answer 1

A. The mass of the iron is 93.6 kg, the weight is 920 N, and the buoyant force is 117.6 N.

Step-by-step explanation:

The mass of the iron can be calculated using the formula:

Mass = Density × Volume

mass = 7800 kg/m³ × 0.012 m³ = 93.6 kg

The weight of the iron can be calculated using the formula:

Weight = Mass × acceleration due to gravity

Weight = 93.6 kg × 9.8 m/s² = 920 N

The buoyant force on the iron can be calculated using the formula:

Buoyant force = density of water × volume of water displaced × acceleration due to gravity

Buoyant force = 1000 kg/m³ × 0.012 m³ × 9.8 m/s² = 117.6 N