Question

In a solution of potassium hydroxide, koh, the ph is found to be 12.80. calculate thehydronium ion concentration, [h3o ], and the hydroxide ion concentration, [hot], in thesolution. kw = 1 * 10 ^ - 14

Answer 1

The hydronium ion concentration and hydroxide ion concentration in a solution of potassium hydroxide with a pH of 12.80 are both 1.58 x 10^(-13) M.

Step-by-step explanation:

The pH of a solution is a measure of its acidity or alkalinity. In a solution of potassium hydroxide (KOH) with a pH of 12.80, the hydronium ion concentration ([H3O+]) can be calculated using the equation:

[H3O+] = 10^(-pH)

Substituting the given pH value, we get:

[H3O+] = 10^(-12.80) = 1.58 x 10^(-13) M

Since water is neutral, the hydronium and hydroxide ion concentrations are equal, which means [H3O+] = [OH-]. Therefore, the hydroxide ion concentration ([OH-]) in the solution is also 1.58 x 10^(-13) M.