Question

In a biology lab, students are investigating the rate of oxygen diffusion through a cell membrane. through their experiment, students have collected the following data : diffusion coefficient = 0.002 cm^2/s surface area =10 cm^2 change in pressure = 5mg /cm^3 distance over which diffusion occurs = 0.5cm what is the rate of oxygen diffusion through the membrane in this experiment?

Answer 1

The rate of oxygen diffusion through the membrane in the biology lab experiment is 0.2 mg/(s·cm), calculated using the formula J = (D × A × ΔC) / δx with the given values of diffusion coefficient, surface area, change in pressure, and distance over which diffusion occurs.

Step-by-step explanation:

To determine the rate of oxygen diffusion through the cell membrane in this biology lab experiment, we can apply the formula that defines the rate of diffusion based on several factors, including the diffusion coefficient (D), the surface area (A), the difference in concentration or pressure (ΔC), and the distance over which diffusion occurs (δx). The rate of diffusion (J) can be calculated using the equation J = (D × A × ΔC) / δx. Plugging in the given values, we have:

J = (0.002 cm²/s × 10 cm² × 5 mg/cm³) / 0.5 cm

J = (0.02 cm³/s × 5 mg/cm³) / 0.5 cm

J = (0.1 mg/s)/0.5 cm

J = 0.2 mg/(s·cm)

This means the rate of oxygen diffusion through the membrane in this experiment is 0.2 mg/(s·cm).