Question

Solve by factoring2x^2+3x=2

Answer 1

The given equation is,

`2x^2+3x=2`

Converting to the standard quadratic form, ax² + bx + c = 0, we have,

`2x^2+3x-2=0`

We have the solution for the quadratic equation as,

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

Here,

`\begin{gathered} a=2 \\ b=3 \\ c=-2 \end{gathered}`

Substituting, we get,

`\begin{gathered} x=\frac{-3\pm\sqrt[]{3^2-(4)(2)(-2)}}{2*2} \\ =\frac{-3\pm\sqrt[]{9+16}}{4} \\ =(-3\pm5)/(4) \\ =(-3+5)/(4);(-3-5)/(4) \\ =(1)/(2);-2 \end{gathered}`