Final answer:
To calculate the heat rejected by a refrigerator with a coefficient of performance of 5.0 and 72 J of work done, first find the heat extracted from the cold reservoir (Qc), which is 360 J. Then, add the work done to Qc to get the total heat rejected to the room, which is 432 J.
Step-by-step explanation:
If the coefficient of performance for a refrigerator is 5.0 and 72 J of work are done on the system, the amount of heat rejected to the room can be calculated using the following relationship: CoP = Qc / W Where CoP is the coefficient of performance, Qc is the heat extracted from the cold reservoir, and W is the work done on the system. In this scenario, we have to find the heat rejected to the hot reservoir (Qh), which can be expressed as: Qh = Qc + W Since CoP = 5.0 and W = 72 J, we can calculate Qc as : Qc = CoP × W Qc = 5.0 × 72 J Qc = 360 J Now, we can find Qh: Qh = Qc + W Qh = 360 J + 72 J Qh = 432 J Therefore, the refrigerator rejects 432 J of heat to the room for the given work of 72 J.