Question

If the current in a circuit is 2 minus j 5 amps and the resistance is 1 plus j 3 ohms, what is the voltage? a.) 13 plus j volts b.) 13 plus j 11 volts c.) 17 plus j volts d.) 17 plus j 11 volts submit

Answer 1

The voltage in the circuit can be found using Ohm's law by multiplying the complex numbers representing current (2 - j5 amps) and resistance (1 + j3 ohms), which results in a voltage of 17 + j1 volts.

Step-by-step explanation:

To calculate the voltage in a circuit with a given current and resistance, we use Ohm's law, which states V = I × R, where V is voltage, I is current, and R is resistance. The current given is 2 - j5 amps, and the resistance is 1 + j3 ohms. Multiplying these complex numbers, we get:

(2 - j5) × (1 + j3) = 2 × 1 + 2 × j3 - j5 × 1 - j5 × j3

= 2 + j6 - j5 - j2 × j3 (since j2 = -1)

= 2 + j1 + 15

= 17 + j1 volts.

So, the correct answer is d.) 17 + j1 volts.