Question

If a solution contains 0.012 moles of ca2 ions, 0.048 moles of nh₄ ions, 0.015 moles of hco3 - ions, and 0.010 moles of cl�ions, how many meq of po4 -3 must be present?

Answer 1

To determine the meq of PO4 -3, calculate the total charge of the other ions in the solution and add them together. total charge of the other ions in the solution. The Ca2+ ions have a 2+ charge, so 0.012 moles will contribute 0.024 meq. The NH4+ ions have a 1+ charge, The solution must contain 0.097 meq of PO4 -3 to maintain electrical balance.

Step-by-step explanation:

To determine the meq of PO4 -3 present, we need to calculate the total charge of the other ions in the solution. The Ca2+ ions have a 2+ charge, so 0.012 moles will contribute 0.024 meq. The NH4+ ions have a 1+ charge, so 0.048 moles will contribute 0.048 meq. The HCO3- ions have a 1- charge, so 0.015 moles will contribute 0.015 meq. And the Cl- ions have a 1- charge, so 0.010 moles will contribute 0.010 meq. Adding these values together, we get a total of 0.097 meq. Therefore, the solution must contain 0.097 meq of PO4 -3 to maintain electrical balance.

the meq of PO4 -3, calculate the total charge of the other ions in the solution and add them together. total charge of the other ions in the solution. The Ca2+ ions have a 2+ charge, so 0.012 moles will contribute 0.024 meq. The HCO3- ions have a 1- charge, so 0.015 moles will contribute 0.015 meq. And the Cl- ions have a 1- charge, so 0.010 moles will contribute 0.010 meq. Adding these values together, we get a total of 0.097 meq. The NH4+ ions have a 1+ charge, The solution must contain 0.097 meq of PO4 -3 to maintain electrical balance.