Question

If an object rolls of a cliff with horizontal velocity of 10.83m/s and in the air for 4.72 high is the cliff?

Answer 1

The height of the cliff is approximately 914.18 meters.

Step-by-step explanation:

Given that the object rolls off a cliff with a horizontal velocity of 10.83 m/s, we can use the formula for projectile motion to calculate the height of the cliff. The horizontal velocity doesn't affect the vertical motion, so we can focus on the vertical component of the motion.

Using the formula h = (1/2) * g * t^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time of flight, we can rearrange the equation to solve for h.

Plugging in the given values, the height of the cliff is approximately 914.18 meters.