Final answer:
The PV work done when 83.0 g of ethylene and 125 g of HCl react with a volume change of -66.3 L at atmospheric pressure is 6.72 kilojoules.
Step-by-step explanation:
The amount of pressure-volume (PV) work done by a reaction can be calculated using the formula PV work = -PΔV, where P is the pressure and ΔV is the change in volume. In this case, since the volume change is -66.3 L (which means the gas is being compressed) and the reaction occurs at atmospheric pressure, which is 101.325 kPa (or 1 atm), we first convert the volume to cubic meters (m³) since standard pressure units are in kPa and standard volume units are in m³. We find that -66.3 L converts to -0.0663 m³. We then multiply the pressure by the volume change to calculate the work done in joules (J). Lastly, to convert joules to kilojoules (kJ), we divide by 1000.
Using the above information, the calculation for PV work is as follows:
(-101.325 kPa) * (-0.0663 m³) = 6.72 kJ (positive, since work is done on the system during compression).