Final answer:
To have the same number of particles as 5 grams of salt, one would require approximately 29.25 grams of sucrose. This is calculated by finding the moles of salt and then converting that to grams of sucrose using its molar mass.
Step-by-step explanation:
To calculate how many grams of sugar (sucrose, C₁₂H₂₂O₁₁) are needed to have the same number of particles as in 5 grams of salt (NaCl), we must use Avogadro's number and the molar masses of both compounds. Firstly, we calculate the number of moles of salt and then use the same number of moles to find the mass of sugar needed.
The molar mass of NaCl is approximately 58.44 g/mol. For 5 g of NaCl:
Number of moles of NaCl = (5 g NaCl) / (58.44 g/mol) = 0.0855 moles NaCl
The molar mass of sucrose is approximately 342.30 g/mol. To have the same number of particles (moles) of sugar:
Mass of sucrose = (0.0855 moles) x (342.30 g/mol) = 29.25 grams of sucrose
This result suggests that to have an equivalent number of particles to 5 grams of salt, we need approximately 29.25 grams of sucrose, assuming no other reactions or interactions occur. This is consistent with our rough estimate.