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How many grams of sucrose c12h22o11 must be added to 649g of water to give a solution with a vapor pressure 0.923mmhg less than that of pure water at 20°c? be sure your answer has the correct number of significant digits.

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Final answer:

To find the grams of sucrose to be added to water to achieve a certain vapor pressure, we use the formula for vapor pressure lowering. We calculate the molality of the solution using the given information about water and sucrose, and then convert the moles of sucrose to grams.

Step-by-step explanation:

To calculate the grams of sucrose that must be added to 649g of water to give a solution with a vapor pressure 0.923mmHg less than that of pure water at 20°C, we need to use the formula for vapor pressure lowering.

The formula is: ΔP = Xsolute * Psolvent. We are given that ΔP = 0.923mmHg, Psolvent = 17.5mmHg, and the molecular formula of sucrose is C12H22O11. We can calculate the molality of the solution using the given information about water and sucrose. Then, we can use the molality to calculate the moles of sucrose and convert it to grams.

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