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A flange and pressure vessel are connected by 12M16 (d1= 13.6) bolts. The inner diameter of the pressure vessel is 250mm. The allowable stress of the bolt is 120N/mm². The resultant load on the connected member is 1.5F (F is the operating load. Decide the maximum pressure the bolted joint can carry.

1 Answer

5 votes

The maximum pressure the bolted joint can carry is approximately 4.25

Given the bolt diameter d1 = 13.6 mm, we can find the area using the formula for the area of a circle: Ab = π * (d1/2)²

Ab = 3.14 * (13.6/2)²

Ab ≈ 144.7 mm²

Since there are 12 bolts, At = 12 * Ab.

At = 12 * 144.7

At ≈ 1736.4 mm²

Calculate the total axial force in all bolts (Ft):

Ft = 12 * Fb

Ft = 12 * 17364

Ft ≈ 208368 N

Given the inner diameter of the pressure vessel (D) is 250 mm, we can find the cross-sectional area using the formula: Av = π * (D/2)².

Av = 3.14 * (250/2)²

Av ≈ 49062.5 mm²

Calculate the maximum allowable pressure (Pmax):

Pmax = Ft / Av

Pmax = 208368 / 49062.5

Pmax ≈ 4.25 N/mm²

User Runrig
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